Solve by setting up a system of linear equations with 2 variables and 2 unknowns. two hundred seventy six students enrolled in a freshmen-level chemistry class. by semester’s end, 5 times the number of students passed as failed. find the number of students who passed the chemistry course.

Let us say ,

x=number of students who passed

y=number of students who failed

total number of students =276

x+y=276(1)

We are given 5 times the number of students passed as failed.

x=5y(2)

plugging value of x from (2) in (1),

5y+y=276

6y=276

y=46

x=5y=46*5=230

x=number of students who passed=230

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

5.25 ounces

step-by-step explanation:

divided 3/4 and 6