Determine which of the following statements are true if parabola 1 has the equation f(x)=x^2-4x-12 and parabola 2 has a leading coefficient of 1 and zeros at x = 4 and x = -2. check all that apply. a. parabola 1 has a lower minimum than parabola 2. b. parabola 1 crosses the y-axis higher than parabola 2. c. parabola 1 and parabola 2 have the same line of symmetry. d. parabola 1 and parabola 2 have a zero in common.

the correct answers are

Parabola 1 and Parabola 2 have a zero in common.

Parabola 1 has a lower minimum than Parabola 2.

First of all, we have to find Parabola 2. The general formula is

.

It is given that the leading coefficient is 1, then a=1. Putting 4 and -2 into the formula, we have to solve the following system of equations:

Solving it, we find that b=-2 and c=-8

Parabola 2 is given with

Both functions have a minimum because the parabolas located upwardly. The minimum of Parabola 1 is located below the minimum of Parabola 2. You can observe this result in the attached picture, as well. Parabola 1 is given with blue line.

your answer would be 10x - 1