During a rock concert, the noise level (in decibels) in front row seats has a mean of 95 db with a standard deviation of 5 db. without assuming a normal distribution, find the minimum percentage of noise level readings within 5 standard deviations of the mean during a rock concert, the noise level (in decibels) in front row seats has a mean of 95 db with a standard deviation of 5 db. without assuming a normal distribution, find the minimum percentage of noise level readings within 5 standard deviations of the mean

We know about Chebyshev's theorem, we can find minimum percentage of noise level readings within 5 s.d. of the mean by using the following formula:-

Here the value of x=5 given in the question.

So

So final answer is 0.96 or 96%.

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