Isosceles right triangle abc has a hypotenuse, ab, with a length of 18 feet. find the exact lengths of the other two sides, ac and bc. ac = a0√ a1 feet bc = a2√ a3 feet to the nearest square foot, find the area of abc . area of abc = a4 square feet

we know that

if ABC is an isosceles right triangle

then

side AC=side BC

angle A=angle B=45 degrees

cos B=adjacent side angle B/hypotenuse

adjacent side angle B=BC

hypotenuse=AB> 18 ft

angle B=45 degrees

cos 45°=(√2)/2

so

cos 45°=BC/AB> solve for BC

BC=AB*cos 45> BC=18*(√2)/2> BC=9√2 ft

AC=BC> AC=9√2 ft

the answer part 1) is

the exact lengths of the two sides, AC and BC is

AC=9√2 ft

BC=9√2 ft

Part b) Find the Area of triangle ABC

Area=b*h/2> AC*BC/2> (9√2)*(9√2)/2> 81 ft²

the answer part b) is

the area of triangle ABC is equal to 81 ft²

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.