An object is thrown in the air with an initial velocity of 5 m/s from a height of 9 m. the equation h(t) = –4.9t2 + 5t + 9 models the height of the object in meters after t seconds. about how many seconds does it take for the object to hit the ground? round your answer to the nearest hundredth of a second.
question 11 options:
0.94 seconds
1.50 seconds
2.00 seconds
9.00 seconds

The time taken by the object to hit the ground is 2 seconds.

Step-by-step explanation:

It is given that,

Initial velocity of an object, u = 5 m/s

Height, h = 9 m

The equation that models the height of the object in meters after t seconds is :

We have to find the time for the object to hit the ground.

i.e.        

On solving the above quadratic equation, we get the value of time t is :

t = 1.958 seconds

or

t = 2 seconds

Hence, the correct option is (c) " 2 seconds ".      

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation:

i suppose it should be (y=2x-5)

step-by-step explanation: