Point p is the center of two concentric circle pq =2.5 and ps= 5 rs is tangent to the smaller circle and a chord of the larger circle what is length of rs to the nearest tenth

Here Q and S are the points on smaller and larger circles respectively and P is the center of both circles.

Given that, radius of smaller circle, PQ= 2.5

and radius of larger circle, PS= 5

RS is a chord of the larger circle and tangent to the smaller circle at point Q.

That's why, ∠PQS will be 90° and the ΔPQS is a right angle triangle.

For ΔPQS, we will use Pythagorean Theorem, according to this theorem here:

(PS)² = (PQ)² + (QS)²

⇒ (5)² = (2.5)² + (QS)² [By plugging PS= 5 and PQ= 2.5]

⇒ 25 = 6.25 + (QS)²

⇒ 18.75 = (QS)² [Subtracting 6.25 from both sides]

⇒ QS = √18.75

⇒ QS = 4.3301

Here Q is the midpoint of the cord RS, so RQ= QS

That means, RS = 2× QS

= 2× 4.3301

= 8.6602

= 8.7 [Rounding to the nearest tenth]

So, the length of RS to the nearest tenth is 8.7

-22

times both sides by 2, times () by 8, add alile terms, move terms, add alike and caculate divide both sides by 3

circumference divided by 3.141592654 then timesthe radius twice

step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice