Given the system of equations 2x+5y=21 x+2y=6 what is the value of x

2x+5y=21 (1st)

x+2y=6 (2nd)

Multiply (2nd) equation by 2 to eliminate x

2x+4y = 12 (2nd)

Now you have:

2x + 5y =21 (1st)

2x + 4y = 12 (2nd)

subtract

y = 9

Substitute y = 9 into (2nd) equation x+2y=6

x + 2(9) = 6

x + 18 = 6

x = -12

Answer

The value of x is -12

391.6 is the correct answer

can someone me: the midsegment through the legs of an isosceles triangle is 4 in. find the sides of the triangle if its perimeter is 20 in. ,   and point g is the centroid of the right △abc with hypotenuse ab=18 in. find cg.