What is the slope of a the line that passes through (0,1) and is parallel to y=5x+3

Parallel lines have equal slopes.

The line y = 5x + 3 has slope 5, so the other line also has slope 5.

The slope is 5.

y = 5x + 3 this line has slope = 5

parallel line, slope is the same

so the slope of a the line that passes through (0,1) and parallel to y=5x+3 is also equal 5

answer

5

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.