We toss a die three times. among all possible outcomes, how many have at least one occurrence of "6"?

There are 6×6×6 = 216 possible outcomes. Of those, 5×5×5 = 125 of them will be outcomes that do not have any occurrences of 6. The number that will have at least one occurrence of 6 is 216 - 125 = 91.

5×5×5 counts the number of ways that the numbers 1–5 might be rolled on 3 rolls.

a; x = 0.5

step-by-step explanation:

-10x = -5

x = 0.5