Suppose that an object is moving along the ground and that the distance (in centimeters) it has travelled after t seconds is given by the formula f(t)=t2 cm. calculate the average speed during the 1 millionth of a second after t=3.

The average speed is the average rate of change of the function.

The average speed during the 1 millionth of a second after t=3 is 6 cm/s

The function is given as:

The average rate of a function is:

1 millionth of a second after t=3 means that:

So, we have:

Expand the numerator

Hence, the average speed during the 1 millionth of a second after t=3 is 6 cm/s

Read more about average speed at:

link

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.