Apoint in the figure is selected at random. find the probability that the point will be in the part that is not shaded

Let r be the radius

Area of the shaded part (which is 2 complete circles)

= 2 x πr²

= 2πr²

Area of the unshaded part (which is a square that has a length 2r)

= 2r x 2r

= 4r²

Probability that the point is in the unshaded area

0.4 (nearest tenth)

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.