1.four hatfields and five mccoys are up for 3 construction jobs in williamson. what is the probability that all 3 jobs go to hatfields? 2.three hatfields and three mccoys are up for 3 construction jobs in williamson. what is the probability that all 3 jobs go to hatfields? 3.four hatfields and six mccoys are up for 3 construction jobs in williamson. what is the probability that all 3 jobs go to hatfields?

To find the probability that the Hatfields will win the jobs, you will find the chance of the Hatfields getting the job in each of the three opportunities and then multiply these together. This process is the same for all three examples given.

Ex 1:

There are 4 Hatfields and 5 McCoys, so 4/9 chance for the first job. The second job there would be 3 Hatfields remaining and only 8 total, so 3/8. Finally there would be 2 Hatfields remaining if 2 of them got the first 2 jobs leaving a total of 7 possible.

4 3 2

9 x 8 x 7 = 1/21 chance

Ex 2:

3 2 1

6 x 5 x 4 = 1/20 chance

Ex 3:

4 3 2

10 x 9 x 8 = 1/30 chance

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x