An irregular polygon is shown below: the area of the irregular polygon is square units.

Area of the Irregular polygon is 26 square unit.

Step-by-step explanation:

Given:

A figure of irregular polygon.

We need to find the are of the irregular figure.

We divide the irregular polygon in to rectangles.

Figure is attached with marking.

AG = 4 unit

AD = CB =  2 units

DF = AG - AD = 4 - 2 = 2 units

Area of the Polygon = Area of rectangle ABCD + Area of rectangle DEFG

                                  = AB × CB + FG × DF

                                  = 4 × 2 + 9 × 2

                                  = 8 + 18

                                  = 26 unit²

Therefore, Area of the Irregular polygon is 26 square unit.

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

.19875994384

step-by-step explanation:

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