Mathematics, 15.07.2019 06:00 kedan12
It is easy to check that for any value of c, the function y(x)=ce−2x+e−x y(x)=ce−2x+e−x is solution of equation y′+2y=e−x. y′+2y=e−x. find the value of cc for which the solution satisfies the initial condition y(−5)=3y(−5)=3.
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It is easy to check that for any value of c, the function y(x)=ce−2x+e−x y(x)=ce−2x+e−x is solution...
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