Area of rectangle with diagonal of 5 in but length not given

Draw a rectangle with diagonal 5 in. Inside this rect. are 2 acute triangles of hypotenuse 5. Note that 3^2 + 4^2 = 5^2; thus the width of the rect. is 3 and the length is 4, with the result that the hypo. is sqrt(3^2+4^2), as expected.

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

probability for j is 1/4

while

a is 1/6