Mathematics, 15.07.2019 11:30 joseenrique02
Find dy/dx when y = ln (sinh 2x). a. 2 cosh 2x b. 2 sech 2x c. 2 coth 2x d. 2 csch 2x
Answers: 1
![\frac{d}{dx}[y]= \frac{d}{dx}[ln(sinh(2x))]](/tpl/images/0092/3195/9c33a.png)
![\frac{dy}{dx} = \frac{1}{sinh(2x) } * \frac{d}{dx}[sinh(2x)]](/tpl/images/0092/3195/0bfc5.png)
![\frac{dy}{dx} = \frac{1}{sinh(2x) } * cosh(2x) * \frac{d}{dx}[2x]](/tpl/images/0092/3195/5cee2.png)
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Find dy/dx when y = ln (sinh 2x). a. 2 cosh 2x b. 2 sech 2x c. 2 coth 2x d. 2 csch 2x...
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