The sum of three numbers is 148. the first number is 10 less than the second. the third number is 4 times the first. what are the numbers?

A) f + s + t = 148
B) f + 10 = s

C) t = 4 * f

Substituting C) into A)
A) f + s + 4f = 148
Substituting B) into A)
A) f + f + 10 + 4f = 148
A) 6f = 138
f = 23
B) f + 10 = s
s = 33
t = 4 * 23
t = 92
23 + 33 + 92 = 148

Try d cause last i guessed that and it was right