Gerald is constructing a line parallel to line l through point p. he begins by drawing line m through points p and q. he then draws a circle centered at q, which intersects line l at point n and line m at point s. keeping the compass measure, he draws a congruent circle centered at point p, which intersects line m at point t. which next step will create point r, such that when a line is drawn through points p and r, the line will be parallel to line l? use the compass to construct a circle centered at q through point p. using the compass measure between points s and n, draw an arc to the right of line m, centered at t, intersecting the edge of circle p. using the compass measure between points s and n, draw an arc above line l, centered at n, intersecting the edge of circle q. use the compass to construct a circle centered at p through point q.

ANSWER IS :Using the compass measure between points S and N, draw an arc to the right of line m, centered at T, intersecting the edge of circle P.

just took this test got it right.

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true