(14.14) larry reads that 1 out of 6 eggs contains salmonella bacteria. so he never uses more than 5 eggs in cooking. if eggs do or don't contain salmonella independent of each other, find the probability (±±0.01) that at least 1 of larry's 5 eggs contains salmonella. rn note: be sure you read the question as 'at least 1' and not instead just find the prob of exactly one. probability is about

we know that

The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.

The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.

If the probability that any one egg has 1/6 chance of salmonella

then

the probability that any one egg will not have salmonella = 5/6.

Therefore

for all 5 to not have salmonella

= (5/6)^5 = 3125 / 7776

= 0.401877 = 0.40 to 2 decimal places

REMEMBER this is the probability that NONE have salmonella

Therefore

the probability that at least one does = 1 - 0.40

= 0.60

the answer is

0.60 or 60%

351.23

step-by-step explanation: