In a gallup poll, 1025 randomly selected adults were surveyed and 57% of them said that they used the internet for shopping at least a few times a year. construct a 99% confidence interval for the true proportion of adults who use the internet for shopping.

The confidence interval for the true proportion of adults who use the Internet for shopping is \left( {0.53,0.61} \right).

Further Explanation:

Proportion of true mean follows normal distribution with mean and variance .

Confidence interval of proportion of mean can be expressed as,

Given:

The total number of adults selected is .

of adults use internet for shopping from adults.

Calculation:

The level of significance is .

The value of is that can be obtained from the standard normal table.

The formula for margin of error is,

The margin of error can be obtained as,

The confidence interval can be obtained as,

The confidence interval for the true proportion of adults who use the Internet for shopping is .

Learn more:

1. Learn more about normal distribution

2. Learn more about standard normal distribution

3. Learn more about confidence interval of mean

Answer details:

Grade: College

Subject: Statistics

Chapter: Confidence Interval

Keywords: Z-score, Z-value, binomial distribution, standard normal distribution, standard deviation, criminologist, test, measure, probability, low score, mean, repeating, indicated, normal distribution, percentile, percentage, undesirable behavior, proportion, empirical rule.

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step-by-step explanation:

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