Plll write the relation as a set of ordered pairs. a. ordered pairs: {(–3, 3), (0, 0), (2, –2)} b. ordered pairs: {(3, –3), (0, 0), (–2, 2)} c. ordered pairs: {(3, –3), (0, 0), (2, 2)} d. ordered pairs: {(–2, 2), (0, 0), (3, –3)}

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5