Which equation represents the circle described? the radius is 2 units. the center is the same as the center of a circle whose equation is x^2+y^2-8x-6y+24=0

X^2 + y^2 - 8x - 6y + 24 = 0
Completing the square:-
(x - 4)^2 - 16 + (y - 3)^2 - 9 + 24 = 0

(x - 4)^2 + (y - 3)^2  =  1

The equation we need has same center (4,3) and radius 2  so its equation is

(x - 4)^2 + (y - 3)^2 = 2^2

     Answer  is (x - 4)^2 + (y - 3)^2 = 4