Sanjay graphs a quadratic function that has x-intercepts of –3 and 7. which functions could he have graphed? check all that apply. g(x) = x2 – 4x – 21 g(x) = (x – 3)(x + 7) g(x) = 3x2 – 12x – 63 g(x) = –(x + 3)(x – 7) g(x) = x2 + 4x – 21

The quadratic function that has x-intercepts of –3 and 7 is g(x) = x² - 4x - 21

A quadratic equation is in the form:

y = ax² + bx + c

where a, b and c are constants, y, x are variables.

Given that the x intercepts are -3 and 7, hence the roots of the polynomial are -3 and 7. Hence:

x = -3 or x = 7

x + 3 = 0 or x - 7 = 0

(x + 3)(x - 7) = g(x)

g(x) = x² - 4x - 21

The quadratic function that has x-intercepts of –3 and 7 is g(x) = x² - 4x - 21

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3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c