given that a♥b = 2 a ( 3 2 − b) if a♥b = − 2 3 , solve for b in terms of a. a) b = 1 6 a + 3 2 b) b = 1 3 a + 3 2 c) b = 1 2 a + 3 2 d) b = 1 6 a − 3 2 me i need  

First of all, write these in a way people can read them in the future. Don't make it so hard to help you.

Secondly:

Given that a♥b = 2a(32− b)

If a♥b = −23, solve for b in terms of a.

A)b = 16a + 32
B)b = 13a + 32
C)b = 12a + 32
D)b = 16a − 32

-23 = 2a(32− b),  devide both sides by 2a -23/2a = 32 - b, subtract 32 from both sides -23/2a - 32 = -b, multiply both sides by -1  23/2a + 32 = b

verified:
b = 23/2a + 32 
-23 = 2a(32 − (23/2a + 32))
-23 = 2a(32 -23/2a -32)
-23 = 2a(-23/2a)
-23 = -23

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Rounding decimals is very similar to rounding other numbers. if the hundredths and thousandths places of a decimal is forty-nine or less, they are dropped and the tenths place does not change. for example, rounding 0.843 to the nearest tenth would give 0.8. , your welcome !