Aprojectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. the path of the projectile is modeled using the equation h(t) = –16t2 + 48t + 190.approximately when will the projectile hit the ground? a. 1.5 secondsb. 3.2 secondsc. 5.3 secondsd. 6.2 seconds

For this case we have the following quadratic equation:
 
 By the time the projectile hits the ground we have the final height equal to zero:
 
 Therefore, we have a second-order polynomial that we must solve:
 Using resolver we have:
 
 Rewriting:
 
 
 Doing the calculations we have two roots:
 
 We discard the negative root because we are looking for time which is greater than zero.
 
 the projectile will hit the ground after:
 C. 5.3 seconds

The answer for this is 9/1253decimal form 0.007