Ihave a question for yall, im doing a sample work in geometry and its like this unit 2 distant forumla midpoint formula and so what do i do here

The appropriate thing to do is what you would do with any math.
• Study the reference material and examples you are given, making sure you understand where the formulas apply and how they are used.
• Memorize the formulas you cannot derive easily based on the understanding you have.
• Work homework and extra problems until you can apply the formulas quickly and easily to any problem to which they are relevant.


The distance formula is based on the Pythagorean theorem. For a right triangle of side lengths a and b and hypotenuse c, the Pythagorean theorem tells you
  c² = a² + b²
Taking square roots, you get
  c = √(a² + b²)

When "a" and "b" are the differences of coordinates in the Cartesian plane, this becomes the distance formula:
  d = √((x₂-x₁)² + (y₂-y₁)²)

You can arrive at the midpoint formula a number of ways. I find it convenient to remember that the coordinates of a midpoint are simply the average of the coordinates of the end points. That is,
  for midpoint M = (mx, my), and endpoints A = (ax, ay), and B = (bx, by)
  M = (A+B)/2
  (mx, my) = ((ax +bx)/2, (ay +by)/2)

This is what i found “answer: a rigid transformation preserves both the side lengths and the angle measures of a polygon. step-by-step explanation: rigid transformations are the transformations which does not affect the size and the shape of figure .” i hope this you for what your looking for. can you plz mark me brainliest?