The base of a triangular prism is an isosceles right triangle with a hypotenuse of 72 centimeters. the height of the prism is 7 centimeters. find the surface area of the triangular prism. round your answer to the nearest tenth.

First, we need to find the length of the other two sides of the triangle using pythagorean theorem: the sum of the squares of the perpendicular sides (base and height) is equal to the square of the hypotenuse). For an instance, s represents the length of base/height.
a² + a² = h²
2a² = 72²
2a² = 5,184
a² = 5,184/2
a² = 2,592
a² = 1,296 × 2
a  = 
a  = 36√2

Second, find the surface area
The surface of prism consists of two bases and lateral sides.
sa = 2 base area + 3 lateral sides
sa = (2 × 1/2 × base of triangle × height of triangle) + perimeter of triangle × height of prism
sa = (2 × 1/2 × 36√2 × 36√2) + (36√2+36√2+72) × 7
sa = 2,592 + (72√2 + 72) × 7
sa = 2,592 + 72(√2 + 1) × 7
sa = 2,592 + 504 (√2 + 1)
sa = 2,592 + 504 (2,4142..)
sa = 2,592 + 1,216.7636
sa = 3,808.7636
to the nearest tenth
sa = 3,808.8 cm²

The surface area is 3,808.8 cm²

Ithink the answer will be d yes