Which points are solutions to the linear inequality y < 0.5x + 2? check all that apply. (–3, –2) (–2, 1) (–1, –2) (–1, 2) (1, –2) (1, 2)

A)

C)  

E)  

F)

Step-by-step explanation:

we have

we know that

If a ordered pair is a solution of the inequality

then

the ordered pair must be satisfy the inequality

Verify

Point A)

Substitute the value of x and value of y in the inequality an compare

-------> is true

The ordered pair is a solution of the inequality

Point B)

Substitute the value of x and value of y in the inequality an compare

-------> is not true

The ordered pair is not a solution of the inequality

Point C)

Substitute the value of x and value of y in the inequality an compare

-------> is true

The ordered pair    is a solution of the inequality

Point D)

Substitute the value of x and value of y in the inequality an compare

-------> is not true

The ordered pair is not a solution of the inequality

Point E)

Substitute the value of x and value of y in the inequality an compare

-------> is true

The ordered pair   is  a solution of the inequality

Point F)

Substitute the value of x and value of y in the inequality an compare

-------> is true

The ordered pair   is  a solution of the inequality

1. 3. can also be expressed as (22/7)

2. -4.5

3. 3.6

happy to

pls mark as brainliest

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0