What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (−2, 4)? y = – x – 1 y = – x + 5 y = x – 1 y = x + 5

First things first.  Solve the equation for y, getting it into y = mx + b form so it's easy to determine the slope.  5x + 2y = 12 so 2y = -5x + 12.  Dividing everything by 2 we get .  So the slope is -5/2.  Parallel lines have the same slope, so we will have a slope of -5/2 in our new equation, we just have to find out what that equation is.  We have an x and a y value from the point, so we will use that, along with the slope, to find b, the y-intercept.  and 4 = 5 + b.  So b = -1.  Now let's write the equation: .  And there you go!

5\16 x 2\5 = 10/80simplify to 1/80