The area of the larger circle is 36 in2. find the circumference of one of the smaller circles.
a. 3 in.
b. 6 in.
c. 9 in.
d. 18 in.

The correct question is
The area of the larger circle is 36pi in(squared). Find the circumference of one of the smaller circles.

A=3pi in.
B=6pi in.
C=9pi in.
D=18pi in
the picture in the attached figure

we know that 
area of a circle=pi*r²
area of the larger circle=36*pi in²
36*pi=pi*r²
r²=36
r=√36-------> r=6 in

the diameter of one of the smaller circles is equal to the radius of the larger circle
so
diameter smaller circle=6 in

circumference=pi*D
where D is the diameter
so
the circumference of one of the smaller circle=6*pi in

the answer is
6*pi in