In a kitchen there are three containers that can hold different quantities of water, as shown in the figure below: three containers of the same shape but different sizes are shown, starting with the shortest and ending with the longest. the following quantities are written below the containers. x minus 10 liters below the first, x minus 5 liters below the second, and x liters below the third. how many liters of water can the three containers hold in all? x − 15 3x − 15 x3 + 50 3x3 − 15

3x - 15

Explanation:
Before we begin, remember the following:
ax + bx = (a+b)x
xᵃ * xᵇ = x⁺ᵇ

Now, for the given:
We have:
volume of first container = x - 10 liters
volume of second container = x - 5 liters
volume of third container = x liters

The volume of water that can be contained in the three containers together would be the SUMMATION of the three volume.

This summation can be computed as follows:
x - 10 + x - 5 + x = x + x + x - 10 - 5
                            = 3x - 15 liters

Hope this helps :)

The answer is: a = about 63.59ft2 for 15