Dult tickets to the fall play cost $8 and student tickets cost $4. the drama class sold 20 more adult tickets than student tickets to the fall play. if the class collected $880 from ticket sales, how many adult tickets were sold? the drama class sold adult tickets.

So for this we'll be using the system of equations. The first equation is gonna be representing the cost of the tickets and the second equation is gonna represent the number of adult tickets sold.

Let x equal # of adult tickets and y equal # of student tickets

The first equation is 
The second equation is 

For this, I'll be using the substitution method. And to do that, we can substitute x in the first equation for (y+20) since that is the equivalent according to the second equation.

And so your first equation should look like this:  . And from there we can solve.

Multiply 8 and (y+20), and your equation should look like 

Combine like terms to get 

Subtract 160 on each side to get 

And then divide 12 on each side and your answer should be 

Now that we know that y=60, we can substitute y for 60 in either equation to solve for x. For this, i'll be using the second equation.



The drama class sold 80 adult tickets.

The distance from point a to point c across the coordinate plane is aproxamatly 8.94 rounded to the nearest hundredth. you use a^2 + b^2 =c^2