Answers: 2
![\bf log_2(2x^3-8)-2log_2(x)=log_2(x) \\\\\\ log_2(2x^3-8)-log_2(x^2)=log_2(x)\implies log_2\left( \cfrac{2x^3-8}{x^2} \right)=log_2(x) \\\\\\ \textit{since both sides are getting }log_2\textit{ we can simply undo that} \\\\\\ \cfrac{2x^3-8}{x^2}=x\implies 2x^3-8=x^3\implies x^3-8=0 \\\\\\ x^3=8\implies x=\sqrt[3]{8}\implies x=2](/tpl/images/0100/6252/d648a.png)
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