Shape i is similar to shape ii. the sequence of transformations applied to shape i that proves shape i is similar to shape ii is a reflection across the , and then a dilation by a scale factor of .

Shape I is located in quadrant IV. Shape II is located in quadrant III.

Shape I has positive x-values and negative y-values.
Shape II has negative x-values and negative y-values.

From this information, we can conclude that shape I was reflected over the y-axis.

This shape has a defined length that we can use to find the scale dilation.

Look at the points (2,-4) and (5,-4) on shape I. These points represent corners of the shape, and we can use these points to find the length of the shape by subtracting the x-values as an absolute value:



The length of the shape is 3 units.

Now we'll look at shape II.

The same line that we used in shape I is present on points (-7.5,-6) and (-3,-6). We can find the length by subtracting the x-values as an absolute value:



The length of shape II is 4.5.

Divide the length of shape II by the length of shape I:



The dilation's scale factor is 1.5.

(-0, -7) is your answer