Quadrilateral jklm was dilated according to the rule do,(x, y) to create the image quadrilateral j'k'l'm', which is shown on the graph. what are the coordinates of vertex j of the pre-image? (0, -4) (0, -1) (0, 0) (0, 4)

The coordinates of vertex J of the pre-image is (0, -4)

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, translation and dilation.

Dilation is the increase or decrease in the size of a figure by a factor k. The dilated figure has the same shape as the original figure.

Given the dilation (x, y) ⇒ [(1/2)x, (1/2)y] on quadrilateral JKLM to produce quadrilateral J'K'L'M'.

The vertex J' has coordinates (0, -2). Hence the coordinates of J = (0, -4)

The coordinates of vertex J of the pre-image is (0, -4)

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i will take them

step-by-step explanation:

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.