What are the answers to these 2 question 4& 5 plz

The first problem:

y = -2 x²  ⇒⇒⇒ x² = -y/2 →(1)33 x² + y² = 27 → (2)
By substitution from (1) at (2) with the value of x²
∴ 33 (-y/2) + y² = 27
∴ y² - 16.5 y - 27 = 0
a = 1 , b = -16.5 , c = -27
∴
∴ y = 18 or y = -3/2
By substitution from at (1) with the value of y
for y = 18   ⇒⇒⇒ x² = -18/2 = -9 (unacceptable)
for y = -3/2 ⇒⇒⇒ x² = -(-3/2)/2 = 3/4
∴
The correct options are 2 , 7
Solution of the system of equations is 

and   

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The second problem:
The general equation of the hyperbole is 

For the given equation:

a² = 225 ⇒⇒⇒ a = √225 = 15
b² = 36   ⇒⇒⇒ b = √36 = 6
∴ the slope of the asymptotes = b/a   and  -b/a

b/a = 6/15 = 2/5

-b/a = -6/15 = -2/5

∴ m = 2/5   and   m = -2/5

Yes you do, so £1973.09 - £1473.50 = £499.59 so tim overpaid £499.59 .hope this ; )