Complete the two-column proof. given: x/6 + 2 =15 prove: x = 78 x/6 + 2 =15 a. x/6= 13 b. x = 78 c.

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: