Me with this problem ! i would appreciate it

Area of triangle: 1/2(base)(height)
Area of rectangle: length × width

Find the area of the triangles on the sides first using 1/2(base)(height).
Plug 8 for the base and 6 for the height.

1/2(8)(6) = 24 units²
Multiply 24 by 2 for both of the triangles.
(24)(2) = 48 units²

Find the area of the rectangles of the object using length × width.
For the rectangle on top, you can find the width using the Pythagorean Theorem: a² + b² = c².

Plug in 6 and 8 for a and b, and find c (width).
6² + 8² = c²
36 + 64 = 100
Square root both sides; √100 = 10.
The width of the rectangle on top is 10.

Now plug 20 for the length and 10 for the width.
20 × 10 = 200 units²

For the rectangle on the bottom, plug in 20 for the length and 8 for the width.
20 × 8 = 160 units²

For the rectangle on the side, plug in 20 for the length and 6 for the width.
20 × 6 = 120 units²

Add up all the areas ⇒ 48 + 200 + 160 + 120 = 528 units².

The vertex of the quadratic function is (1.5, -.75)

Something that is true about that is that it has numbers