Jade, a pro softball player, hits the ball when it is 3 feet off the ground with an initial velocity of 100 ft/sec and at an angle of 35° from the horizon. a straight line wind is blowing at 14 ft/sec in the direction the ball is traveling. she hits the ball towards a 40-foot fence that is 120 feet from the plate; if it clears the fence, the ball is a home run. (a) will the hit be a home run? (b) if so, how much does it clear the fence? if not, how much does it miss the fence?

The horizontal component of the velocity of the ball will be  100 cos 35 + 14
= 95.92 ft/sec.
The time  for the ball to reach the fence =  120 / 95.92 =  1.251 seconds.
We now have to find the height of the ball after 1.251 seconds.
Vertical component of the velocity = 100 sin 35 =  57.36 ft/second
It has to be at a height of over 40 ft at time 1.251 seconds.

equation of motion is h = 57.36t - 16t^2 + 3 

so we have h = 57.36(1.251) - 16(1.251)^2 + 3 = 49.7 feet
so (a) it will be a home run and
(b) it clears the fence by 9.7 feet.