What is the interquartile range of this data set? 1, 5, 27, 29, 34, 37, 48, 61, 72, 84, 96 a. 45 b. 37 c. 10 d. 64

Choice A) 45



The given set of values is 
A = {1, 5, 27, 29, 34, 37, 48, 61, 72, 84, 96}
The median of this set is 37. Five values are below it; five values are above it. It is the middle most value.

Let
L = {1, 5, 27, 29, 34}
be the lower set of values smaller than the median. We see that the median of set L is 27. So Q1 = 27

Let
U = {48, 61, 72, 84, 96}
which is composed of all the values above the median
The median of the upper set of values is 72. So Q3 = 72

Subtract the first and third quartile values to get the interquartile range (IQR)
IQR = Q3 - Q1
IQR = 72 - 27
IQR = 45

You would need a laid out graph for this but could you provide a picture of just a graph? i can give stepssolve for y.subtract 4xdivide by -1 (opposites)graph slope intercept formcheck each point to see if it’s on the graph