If the area of the rectangle to be drawn is 30 square units, where should points c and d be located, if they lie vertically below a and b, to make this rectangle? a. c(3, −2), d(−2, −2) b. c(3, −3), d(−2, −3) c. c(−3, 3), d(−3, −2) d. c(−2, 3), d(−2, −2)

 B) C(3,-3) and D(-2,-3)

Step-by-step explanation:

We are given that the area of rectangle is 30 square units.

Now, looking at the given figure. the coordinates of A are (-2,3) and coordinates of B is (3,3).

Therefore, length of AB is 5 Units.

Now, we are given that area of the rectangle is 30 square units.

Area of rectangle =

If we consider AB as the breadth of the rectangle therefore, we get, length of the rectangle as 6 units, using the above formula.

Now, given C and D are exactly below B and A.

Thus, the y coordinate of C and D should be 6 units below the coordinates of B and A respectively and their x-coordinates remain the same.

Thus, C have coordinates (3,-3) and D have coordinates (-2,-3)  

answer: the first graph

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.