Wyatt’s eye-level height is 120 ft above sea level, and shawn’s eye-level height is 270 ft above sea level. how much farther can shawn see to the horizon? use the formula d=square root (3h/2), with d being the distance they can see in miles and h being their eye-level height in feet.

The formula is defined in the question as follows:



h is the eye-level height. 

Wyatt's eye-level height is 120. Plug this value into the equation:



Shawn's eye-level height is 270. Plug this value into the equation:



Subtract Wyatt's viewing distance from Shawn's to find their difference:



Shawn can see 6.7082 miles farther than Wyatt.

Ithink the answer is c