How do i work with the x^2? this problem is for circles

I am assuming that you are looking for the point where lines j and k intersect. To find this point, we need to set the equations equal to each other:



Move everything to one side:



Factor:

(x-3)(x-3) = 0

x = 3

If you just looking for x, the answer is x = 3. 

If you need the point, plug x = 3 into either equation to find the y value. Since the two lines intersect at x = 3, either equation will give you the same

k = 4(3) - 6 = 6

The point where the lines intercept is at (3,6).

Set square i think so