Mathematics, 19.07.2019 12:30 zinai123

I’m failing math ya girl which sequence of steps would transform v to v? a. reflect across the x-axis; rotate 180 degrees, counterclockwise about the origin b. reflect across the y-axis; rotate 90 degrees, counterclockwise about the origin c. reflect across the line y= -x, rotate 90 degrees, counterclockwise about the origin d. reflect across the line y=x; rotate 180 degrees counterclockwise about the origin

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I’m failing math ya girl which sequence of steps would transform v to v? a. reflect across the x

Answer from: hellokitty1647

The correct option is C.

Step-by-step explanation:

From the given graph it is clear that the v passing thought the coordinates (4,1) and v' passing thought the coordinates (4,-1).

It meas the relation between v and v' is

$v(x,y)\rightarrow v'(x,-y)$

In option A,

Reflect across the x-axis; rotate 180 degrees, counterclockwise about the origin, then

$v(x,y)\rightarrow v_1(x,-y)\rightarrow v_2(-x,y)\neq v'(x,-y)$

Therefore option A is incorrect.

In option B,

Reflect across the y-axis; rotate 90 degrees, counterclockwise about the origin, then

$v(x,y)\rightarrow v_1(-x,y)\rightarrow v_2(-y,-x)\neq v'(x,-y)$

Therefore option B is incorrect.

In option C,

Reflect across the line y= -x, rotate 90 degrees, counterclockwise about the origin, then

$v(x,y)\rightarrow v_1(-y,-x)\rightarrow v_2(x,-y)=v'(x,-y)$

Therefore option C is correct.

In option D,

Reflect across the line y=x; rotate 180 degrees counterclockwise about the origin, then

$v(x,y)\rightarrow v_1(y,x)\rightarrow v_2(-y,-x)\neq v'(x,-y)$

Therefore option D is incorrect.

Answer from: Quest

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Answer from: Quest

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true

Bwill make the inequalities y < 2x + 1 and y> -x- 2 true. o a. region b o b. region c o c. r

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