How many different positive integers of 2 digits each can be made with the digits 2, 4, 5, and 8, if no digit is repeated in a number? 8 12 16

12

Step-by-step explanation:

Given : The total number digits given : 4

Since repetition is not allowed then to find the number of different positive integers of 2 digits each can be made with the digits 2, 4, 5, and 8 we use permutations.

We know that the permutation of n things taking m at a time is given by :-

Similarly, the number of permutations of 4 things taking 2 at a time is given by :-

Hence, the required number of different positive integers = 12.

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6