Using cramer’s rule, what is the value of x in the system of linear equations below? x+3y=16 3x+y=8

We know that
Cramer's rule works as follows:
x+3y=16
3x+y=8
Then
x=Dx/D
y=Dy/D
where Dx,Dy,D are 2x2 matrices formed from of coefficients and right hand side.
D=
1 3
3 1
=1-9=-8
Dx=matrix D with first column replaced by the vector [16,8]=
16 3
 8  1
=16-24=-8
Dy=matrix D with second column replaced by the vector [16,8]=
1 16
3  8
=8-48=-40

therefore
x=-8/-8=1
y=--40/-8=5

the answer is
x=1
y=5

The third and fourth box.

I’m confused as to what you are asking 66 2/3 percentage wise