If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation h= -16^2+vt+s, where h is in feet. if the object is propelled from a height of 12 feet with an initial velocity of 96 feet per second its height h is given by the equation h= -16t^2 +96t+12. after how many seconds is the height 120 feet?

Combine the information in the problem and the chart using the average balance method to solve the problem.

1yd 1 ft = 1 1/12 1 1/3 1 1/2 1 1/6

For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)