What is the area of the figure? [__] mm2

Given:
2 shapes are present. 2 Right triangles and trapezoid

Area of right triangle =  ab / 2
a = 12 mm
b = 18 mm/ 2 = 9mm

A = (12mm * 9mm)/2 = 108mm²/2 = 54mm²

There are 2 right triangles so; A = 54mm² * 2 = 108mm²

Area of a Trapezoid = (a+b)/2 * h
a = 14mm
b = 18mm
h = 17mm -12mm = 5mm

A = (14mm + 18mm)/2 * 5mm
A = 32mm/2 * 5mm
A = 16mm * 5mm
A = 80mm²

Total Area = Triangles + Trapezoid
T.A. = 108mm² + 80mm²
T.A. = 188mm²

Answer:

$4034.40

step-by-step explanation:

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40