Will mark brainliest!in triangle pqr, mp= 43, pq=7.5 and pr= 8.4. what is mr to the nearest degree? a. 64 b. 52 c. 41 d. 60 in triangle abc ma=43, mb=62 and bc=22 in. what is ab to the nearest tenth of an inch? a. 28.5 b. 15.6 c. 14.1 d.31.2 you.

Part 1) In triangle PQR, mP= 43, PQ=7.5 and PR= 8.4. What is mR to the nearest degree?

we know that
the law of cosines establishes that
c²=a²+b²-2*a*b*cos C

in this problem

c=QR
a=PQ=7.5
b=PR=8.4
C=angle P=43°
c²=a²+b²-2*a*b*cos C> c²=7.5²+8.4²-2*7.5*8.4*cos 43°
c²=34.66> c=5.89
QR=5.9 

applying the law of sines
7.5/sin R=5.9/sin 43> 7.5*sin 43=5.9*sin R---> sin R=7.5*sin 43/5.9
sin R=0.8669> R=arc sin (0.8669)> R=60.11°> R=60°

the answer Part 1) is the option
D. 60

Part 2) In triangle ABC mA=43, mB=62 and BC=22 in. What is AB to the nearest tenth of an inch?

we know that 
∠C=180-(62+43)> ∠C=75°

Applying the law of sines
22/sin 43=AB/sin 75> AB=22*sin 75/ sin 43> AB=31.16 in
AB=31.2 in

the answer Part 2) is
D.31.2

Horizontal change or the change of x