Find the center and radius of the circle whose equation is x 2 + y 2 - 6x - 2y + 4 = 0 (3,1), r = (-3,-1), r = (3,1) r = 6 (9,1), r = 36

Use " ^ " to denote exponentiation:     x^2 + y^2 - 6x - 2y + 4 = 0complete the square (twice): x^2 + y^2 - 6x - 2y + 4 = 0 =>   x^2 - 6x  + 9 - 9 + y^2- 2y + 1 - 1 + 4 = 0from this latest result we get (x-3)^2 + (y-1)^2 = 9+1-3 = 7then the center of the circle is (3,1) and the radius is sqrt(7).